(4%) Problem 19: An object rolls off a tabletop with a horizontal velocity vox-
ID: 1882417 • Letter: #
Question
(4%) Problem 19: An object rolls off a tabletop with a horizontal velocity vox- 22 m/s. The table is at a height yo-1.15 m, above the floor. Use a coordinate system with its origin on the floor directly beneath the point where the object rolls off the table, its horizontal x-axis lying directly beneath the object's trajectory, and its vertical y-axis pointing up. 25% Part (a) How long, in seconds, is the object falling before it hits the floor? 0.484 Correct! 25% Part (b) what's the horizontal distance, in meters, from the edge of the tabletop to where the object lands? x= 10.648 x = 10.65 Correct! 25% Part (c) What is the vertical component of velocity, in meters per second, when the object hits the ground? 4.747 X Attempts Remain Feedback: is available 25% Part (d) What is the magnitude of the velocity (it's speed) when it hits the floor? Grade Summary Deductions Potential 0% 100% sin0 cotan0asin acos0 atan acotan sinh0 cosh0 cotanh0 7 8 9 4 5 6 1 23 (0 Submissions Attempts remaining: 200 (000 per attempt) detailed view END Degrees Radians NO Submit Hint I give up!Explanation / Answer
Vox = 22 m/s
yo = 1.15 m
a )
time t = ( 2 h / g )1/2
= ( 2 yo / g )1/2
= ( 2 X 1.15 / 9.8 )1/2
t = 0.4844 sec
b )
horizontal distance = Vox t
= 22 X 0.4844
= 10.6568 m
c )
the vertical component is
Voy = Viy + a t
= - 9.8 X 0.4844
Voy = - 4.747 m/s
d )
V = ( Vox2 + Voy2 )1/2
= ( 222 + ( - 4.747 )2 )1/2
V = 22.506 m/s
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