%) Problem 9: ke 5.6 m below. An eagle is flying horizontally at a speed of 3.5
ID: 1882439 • Letter: #
Question
%) Problem 9: ke 5.6 m below. An eagle is flying horizontally at a speed of 3.5 m/s when the fish in her talons wiggles loose 50% Part (a) Calculate the magnitude of the velocity of the fish relative to the water when it hits the water in ms. Grade S Deduction Potential vEl sinO cos0 tano 7 8 9 cotan0 asin acos0 atan0 acotan0 sinh0 cosh) tanh cotanh0 Attempts 3%per O Degrees O Radians Submit I give up ints: 1% deduction per hint. Hints remaining: 4 Feedback: 0deduction per feedback. S0% Part (b) Calculate the angle, in degrees, by which the fish's velocity is directed below the horizontal when the fish hits the watExplanation / Answer
a) Vx = 3.5 m/s
Vy = -sqrt [2 g h] = sqrt [2 * 9.8 * 5.6] = -10.48 m/s
V = sqrt [Vx2 + Vy2] = sqrt [3.52 + 10.482]
magnitude of the velocity = 11.0 m/s
b) theta = tan-1(Vy / Vx) = tan-1(-10.48 / 3.5)
= -71.5 deg
phi = 360 - 71.5 = 288.5 deg
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