Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

%) Review 12-14 (algorithmic) Question Help * The data shown graphically below w

ID: 2305432 • Letter: #

Question

%) Review 12-14 (algorithmic) Question Help * The data shown graphically below was collected during testing of an electromagnetic mass driver. The energy to energize the electromagnets was obtained from a bank of capacitors. The capacitor bank was charged to various voltages, and for each voltage, the exit velocity of the projectile was measured when the mass driver was activated Click the icon to view the provided graph. ? (a) What would the velocity be if the capacitors were charged to 100,000 volts? The velocity would be 2.6 10 meters per second. (Round your answer to two significant digits.) (b) What voltage would be necessary to accelerate the projectile to 1,500 meters per second? The required voltage would be volits.(Round your answer to two significant digits) More Info Vp: 114V068 Capacitor voltage (V) kV Print Done

Explanation / Answer

Vp = 114V0.68

where Vp is velocity in m/s

V is voltage in kV

for a)

V = 100000 Volts = 100kV

Vp = 114*(100)0.68 = 2611.58 m/s = 2.61 *103 m/s

b) velocity =Vp= 1500 m/s

1500 = 114 *V0.68

V0.68=13.157

apply log on both sides

0.68log(V) = log(13.157)

log(V) = 1.119 / 0.68

log(V) = 1.64582

V = 101.64582

V = 44.24038 kV

V = 44240.38 volts -------------this would be the voltage required