What type of motion is presented on the graph below? v (m/s) 10 t (s) 10 O posit

Question

What type of motion is presented on the graph below? v (m/s) 10 t (s) 10 O positive velocity with a constant negative acceleration positive velocity with an increasing positive acceleration O positive velocity with a constant positive acceleration positive velocity with a decreasing negative acceleration constant positive velocity Calculate the acceleration using the information provided by the v(c) graph. (Enter your answer to two significant figures.) 2.33 Your value is too high. m/s2 What physical quantity does the slope of the graph represent? O acceleration position o velocity time What is the magnitude of the force that produced this acceleration? The mass of the cart was 125 g. (Enter your answer to two significant figures.) F-0.252

Explanation / Answer

1.

Since velocity is linearly increasing, So it's positive velocity with constant acceleration.

2.

acceleration = slope of V-t graph

acceleration = (V2 - V1)/(t2 - t1)

(t1, V1) = (0, 0)

(t2, V2) = (6 sec, 4 m/sec)

So,

acceleration = (4 - 0)/(6 - 0) = 0.67 m/sec^2

OR if

(t2, V2) = (9 sec, 6 m/sec)

a = (6 - 0)/(9 - 0) = 0.67 m/sec^2

3.

Slope represents acceleration

4.

Using newton's second law:

Fnet = m*a

m = 125 gm = 0.125 kg

Fnet = 0.125*0.67

Fnet = 0.084 N

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