A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very l

Question

A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the masses are gently released, what is the resulting acceleration of the masses? A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the masses are gently released, what is the resulting acceleration of the masses? A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the masses are gently released, what is the resulting acceleration of the masses?

Explanation / Answer

here ,

let the acceleration of the masses is a

using second law of motion

net force = total mass * acceleration

5* 9.8 - 3 * 9.8 = (5 + 3) * a

a = 2.45 m/s^2

the acceleration of the masses is 2.45 m/s^2

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