A brave but inadequate rugby player is being pushed backward by an opposing play

Question

A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800.0 N on him. The mass of the losing player plus equipment is 90.5 kg, and he is accelerating at 1.17 m/s2 backward. (Enter the magnitudes.)

(a) What is the force of friction (in N) between the losing player's feet and the grass?

(b) What force (in N) does the winning player exert horizontally on the ground to move forward if his mass plus equipment is 119.0 kg? (Assume the winning player is accelerating with the losing player at 1.17 m/s2.)

Explanation / Answer

(a) using newton's second law

Fnet = ma

force applied - friction force = ma

800 - friction force = 90.5*1.17

friction force = 694.11 N

(b) F = applied force + ma

F = 800 + 119*1.17

F = 939.23 N

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