PHY2054-U02 Course Home Constants Part A Two circular concentric loops of wire l
ID: 1883494 • Letter: P
Question
PHY2054-U02 Course Home Constants Part A Two circular concentric loops of wire lie on a tabletop, one inside the other. The inner loop has a diameter of 20.0 cm and carries a clockwise current of 120 A, as viewed from above, and the outer wire has a diameter of 30.0 cm What must be the magnitude of the current in the outer loop so that the net magnetic fleld due to this combination of loops is zero at the common center of the loops? Express your answer with the appropriate units. I-Value Units Submit Request Answer Part B What must be the direction (as viewed from above) of the current in the outer loop so that the net magnetic field due to this combination of loops is zero at the common center of the loops? 0 clockwise O counterclockwise Submit Request Answe Provide Feedback Next >Explanation / Answer
Magnetic field from inner wire,
Binner = u0 (12)/20 (into the page)
So outer wire will provide a field with same magnitude but in opposite direction.
Bouter = u0(12)/30
Since, Binner = Bouter
u0 I /30 = u0 (12)/20
So, current, I = 18 A
B)
Current must be counterclockwise
Comment in case any doubt please rate my answer ....
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