/10 points I Previous Answers SerPSE10 27 P014 An electron in a cathode-ray-tube
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/10 points I Previous Answers SerPSE10 27 P014 An electron in a cathode-ray-tube (CRT) accelerates uniformly from 1.00 x 104 m/s to 6.00 x 106 m/s over 1.50 cm My Notes Ask Your (a) In what time interval does the electron travel this 1.50 cm? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. s (b) What is its acceleration? 14421 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m/s2 Need Help? Road 14. -10 points SerPSE10 270P016 My Nates Ask Your A ride-sharing car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 36.0 m/s. Then the vehicle moves for 89.0 s at constant speed until the brakes are applied stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the ride-sharing car in motion (in s)? (b) What is the average velocity of the ride-sharing car for the motion described? (Enter the magnitude in m/s.) m/s Need Help? L 11. 110 pointsSerPSE10 270P01s My Notes Ask Your A particle moves along the x axis. Its position is given by the equation x-1.6 + 2.61-3.Bt2with in meters and t in seconds. (a) Determine its position when it changes direction. (b) Determine its velocity when it returns to the position it had at t-0? (Indicate the direction of the velocity with the sign of your answer) m/s Need Help?LwwchExplanation / Answer
9. vf^2 - vi^2 = 2 a d
(6 x 10^6)^2 - (1 x 10^4)^2 = 2(a)(1.50 x 10^-2)
a = 1.20 x 10^15 m/s^2
vf = vi + a t
6 x 10^6 = 1 x 10^4 + (1.20x 10^15) t
t = 5 x 10^-9 s
(a) 5 x 10^-9
(B) 1.2 x 10^15
10. vf = vi + a t
36 = 0 + 2 t1 => t1 = 18 sec
(A) total time = 18 + 89 + 5 = 112 s
(B) d1 = 0 + (2 x 18^2 / 2) = 324 m
d2 = 36 x 89 = 3204 m
for last section: a = - 36/5 = -7.2 m/s^2
d3 = (0^2 - 36^2)/(2 x -7.2) = 90 m
d = d1 +d2 +d3 = 3618 m
v = d /t = 3618 /112 = 32.3 m/s
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