Chapter 18, Problem 21 Interactive LearningWare 18.2 provides one approach to so

Question

Chapter 18, Problem 21 Interactive LearningWare 18.2 provides one approach to solving problems such as this one. The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q1 = +9.821k; the other two have identical magnitudes, but opposite signs: 92--5.20HC and q3-+5.20c. (a) Determine the net force exerted on qi by the other two charges. (b) If q1 had a mass of 1.50 g and it were free to move, what would be its acceleration? 1.30m 230 130m 43 (a) Number (b) Number Click if you would like to Show Work for this question: Units Units Open Show Work

Explanation / Answer

Electric force due to q2

F2= 9*10^9*6.45*10^-6*5.57*10^-6/(1.3^2)* ( cos 23 i + sin 23 j)

F2= 0.176 i + 0.0748 j

Similarly, Electric force due to q3

F3= - 0.176 i + 0.0748 j

Net force,

F= F1+F2= 2*0.0748= 0.1496 N

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ma= 0.1496

1.5*10^-3*a= 0.1496

a= 99.733 m/s^2

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Plz post other problems seperately

Comment in case any doubt.. good luck

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