A car is traveling around a horizontal circular track with radius r = 160 m at a

Question

A car is traveling around a horizontal circular track with radius r = 160 m at a constant speed v = 28 m/s as shown. The angle A = 21° above the x axis, and the angle B = 57° below the x axis.

1)

What is the magnitude of the car’s acceleration?

m/s2

2)

What is the x component of the car’s acceleration when it is at point A

m/s2

3)

What is the y component of the car’s acceleration when it is at point A

m/s2

4)

What is the x component of the car’s acceleration when it is at point B

m/s2

5)

What is the y component of the car’s acceleration when it is at point B

m/s2

6)

As the car passes point B, the y component of its acceleration is

increasing

constant

decreasing

Explanation / Answer

given

the car is travelling around a horizontal circular track

r = 160 m

v = 28 m/s

thetaa = 21 deg

thetab = 57 deg

1. a = v^2/r = 28^2/160 = 4.9 m/s/s

2. when at point A

x component of car's acceleration = ax

ax = -a*cos(thetaa) = -4.9*cos(21) = -4.574544 m/s/s

3. ay = -a*sin(thetab) = -4.9*sin(21) = -1.7560029 m/s/s

4. at point B

ax = -a*cos(thetab) = -4.9cos(57) = -2.66873127 m/s/s

5. ay = -a*sin(-thetab) = 4.9*sin(57) = 4.10948578 m/s/s

as car crosses point B, y acceleration is decreasing

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.