edge or center of lily pads. She wanted to determine if there was a 1% probabili
ID: 188718 • Letter: E
Question
edge or center of lily pads. She wanted to determine if there was a 1% probability th due to chance alone, so she used a probability (P value) of p = 0.01 . For this low pro is 6.64. Her results showed a calculated 2 value of 7.41 Does she reject or fail t She has rejected her nutt nypotnesis has accapted the aHtemahve hypothesis Tr Why? (2 pts) uanings that her res utts have uss'th in nature. A good Table 105 Animals are often faced with choices dr t example of this is an idea coined "optimal foraging theory." This theory states that foraging animals will try to maximize their en- ergy intake (a benefit, like food or territory), while losing a minimal amount of energy to find a resource (cost) (for more informationQuality on optimal foraging theory, search the web). Foraging behavior de Bee A scribes a particular means by which an animal searches for a food Bee B resource. In many species of foraging insects, like honey bees in the Apis genus, individuals are likely to choose or select the same host plant species to find nectar, which is termed “floral constancy Beep Scientists have suggested that foraging on familiar plant species Bee E throughout a lifetime is less costly, and provides a more predictable Bee F source of food for a bee. 6. Bee C Bee G To test the optimal foraging theory in honey bees, Dr. Beebrain set Bee H up a lab experiment with three fake flowers--each of which had an Bee I unlimited supply of a different quality of nectar (high calorie, low TeeJ calorie, and in between); the fake flowers were otherwise exactly the same. She marked 10 individual bees and allowed them to forage inL the lab for two hours. She observed the foraging and recorded the number of visits each flower received from each bee (Table 10.5). 202
Explanation / Answer
Answer:
1) What would Dr. Beebrain's alternative and null hypothesis be if she plans to use a chi-square test and expects optimal foraging to take place?
Null Hypothesis H0: Number of visits each flower received from each bee is in accordance with optimal foraging theory. There is no significant difference in the observed number of visits received by each flower as compared to expected number of visits received by each flower in accordance with optimal foraging theory.
Alternative Hypothesis Ha: Number of visits each flower received from each bee is not in accordance with optimal foraging theory. There is a significant difference in the observed number of visits received by each flower as compared to expected number of visits received by each flower based on optimal foraging theory.
2) The calculated chi-square value for the experiment is 5.96. Draw a sound conclusion based on this value and the information in the table (assuming a 95% probability threshold). Be sure to address the hypothesis directly.
Probability threshold 95%, significance level = 0.05
Degree of freedom = number of categories - 1 = 3 - 1 = 2
The P-value corresponding to a chi square value of 5.96 with 2 degree of freedom is 0.050793.The result is not significant at p < 0.05. Therefore, the Null Hypothesis is not rejected.
3) Consider this scenario in light of optimal foraging theory. A wolf has two choices:
Option 1:
Option 2:
Since net gain is more in option 2, therefore, wolf should choose option 2.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.