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ecure https://session.rnasteringchemistry.com/myd/mastenng#/assignment/list/5930201 Secure https://session masteringchemistry.com/mycVitemView?assignmentProblemID-93212198 Chuter Analysis of Metalic Oxides Reduction of metallic oxides The reduction of a metalic oxde is represented by this generic equation where M represents the symbol for the metal and z and y are the subseripts in the formula Part C Consider the data in the following table substanc. | r kJ/mol) V Os(s)1550.6 Ha(R) V(s) H O(R)-241.82 Calculate 11-for me reduction for V20s Express your answer using four significant figures Hints kJ My Answers Give Up Part D

Explanation / Answer

Hrxn = Hprod - Hreact

the reaction

V2O5(s) + H2(g) = V(s) + H2Ov

balance

V2O5(s) + H2(g) = 2V(s) + 5H2O(g)

V2O5(s) + 5H2(g) = 2V(s) + 5H2O(g)

now..

HRxn = Hproducts - Hreactants = (2V+ 5H2O ) - (V2O5 + 5H2) = (2*0 + 5*-241.82) - (-1550.6 + 5*0)

HRxn = 341.5 kJ/mol

note that this is based on 1 mol of V2O5

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