For each slope below, enter the value current to four decimal places. Suppose an

Question

For each slope below, enter the value current to four decimal places. Suppose an arrow is shot upward on the moon with a velocity of 25 m/s, then its height in meters after t seconds is given by h(t) = 25t - 0.83t2.Find the average velocity over the given time intervals.[5,6]: [1,5.5]: [5,5.1]: [5,5.01]: [5,0.001]: Box1:Enter your answer as a number (like 5, - 32.2) or as a calculation (like 5/3, 2^3,5 + 4) Enter DNE for Does Not Exit, oo for Infinity Box 2: Enter your answer as a number (like 5, - 32.2) or as a calculation (like 5/3, 2^3,5 + 4) Enter DNE for Does Not Exit, oo for Infinity Box 3: Enter your answer as a number (like 5, - 32.2) or as a calculation (like 5/3, 2^3,5 + 4) Enter DNE for Does Not Exit, oo for Infinity Box 4: Enter your answer as a number (like 5, - 32.2) or as a calculation (like 5/3, 2^3,5 + 4) Enter DNE for Does Not Exit, oo for Infinity Box 5 Enter your answer as a number (like 5, - 32.2) or as a calculation (like 5/3, 2^3,5 + 4) Enter DNE for Does Not Exit, oo for Infinity

Explanation / Answer

instantaneos velocity is given by differential of h(t) = 25 - 1.66t hence average velocity over [5,6] = (25 - 1.66*5 + 25 - 1.66*6)/2 = 25 - 1.66*5.5 = 15.97 hence average velocity over [5,5.5] = (25 - 1.66*5 + 25 - 1.66*5.5)/2 = 25 - 1.66*5.25 = 16.285 hence average velocity over [5,5.1] = (25 - 1.66*5 + 25 - 1.66*5.1)/2 = 25 - 1.66*5.05 = 16.617 hence average velocity over [5,5.01] = (25 - 1.66*5 + 25 - 1.66*6)/2 = 25 - 1.66*5.005 = 16.6917 hence average velocity over [5,5.001] = (25 - 1.66*5 + 25 - 1.66*6)/2 = 25 - 1.66*5.0005 = 16.69917

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