Use linear approximation, i. e. the tangent line, to approximate as follows: Let

Question

Use linear approximation, i. e. the tangent line, to approximate as follows: Let f (x) = . The equation of the tangent line to f (x) at x = 36 can be written in the form y = mx + b where m is: and where b is: Using this: we find our approximation for is NOTE: For this part, give your answer to at least 9 significant figures or use fractions to give the exact answer. Box 1: Enter your answer as a number (like 5, -3, 2. 2) or as a calculation (like 5 / 3, 2^3, 5 + 4) Enter DNE for Does Not Exist oo for Infinity Box 2: Enter your answer as a number (like 5, -3, 2. 2) or as a calculation (like 5 / 3, 2^3, 5 + 4) Enter DNE for Does Not Exist, oo for Infinity Box 3: Enter your answer as a number (like 5, -3, 2. 2) or as a calculation (like 5 / 3, 2^3, 5 + 4) Enter DNE for Does Not Exist, oo for Infinity

Explanation / Answer

y = x^(1/2) dy/dx = (1/2)x^(-1/2) y(36) = 6 y2 = y1 + y'(x1) * (x2 - x1) y(36.4) = y(36) + y'(36)*(36.4 - 36) =6 + (1/(2*sqrt(64)))*(.4) = 6 + (1/(2*6))*(.4) = 6 + (.4)/(12) y(64.4) = 6.03333

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.