A 113.5 -kg uniform bar of length L = 4 m is attached to a wall by a hinge at po

Question

A 113.5-kg uniform bar of length L = 4 m is attached to a wall by a hinge at point A and supported in a horizontal position by a light cable attached to its other end. The cable is attached to the wall at point B, at a distance D = 3 m above point A.

Fhorizontal = Fvertical = A 113.5-kg uniform bar of length L = 4 m is attached to a wall by a hinge at point A and supported in a horizontal position by a light cable attached to its other end. The cable is attached to the wall at point B, at a distance D = 3 m above point A. (a) Find the tension, T, on the cable. (b) Find the horizontal and vertical components of the force acting on the bar at point A. (Enter the magnitude only.)

Explanation / Answer

let the tension be T then from rotational equilibrium

TsinxL=mgL/2

so T=927.86N

from vertical equilibrium

Fvertical+Tsin=mg

Fvertica=556.72N

Fhorizontal=Tcos=&42.29N

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