In the following figure, R1 = 7. 00 ohm , R2 = 6. 00 ohm , and R3 = 6. 00 ohm. T

Question

In the following figure, R1 = 7. 00 ohm , R2 = 6. 00 ohm , and R3 = 6. 00 ohm. The battery has negligible internal resistance. The current I2 through R2 is 5. 00 A What is the current I1, ? Express your answer with the appropriate units. I1 = What is the current I3 ? Express your answer with the appropriate units. I3 = What is the emf of the battery? Express your answer with the appropriate units. Epsilon =

Explanation / Answer

i2=i * r1/(r1+r2) ==>i=5*13/7 ==>i=9.2857 i=i3=9.2857 i1=i3 -i2=9.2857-5=4.2857 ampere r=6 +42/13 =120/13 v=ir=5*13/7 *120/13 =85.7volts

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