Two forces are applied to a tree stump to pull it out of the ground. Force A has
ID: 1899939 • Letter: T
Question
Two forces are applied to a tree stump to pull it out of the ground. Force A has a magnitude of 2030 newtons (N) and points 48.0Explanation / Answer
A > is in (x, -y) quardant A = 2080[cos 32.5 (i) + sin 32.5 (-j)] where (+i) and (+j) are unit vectors in east and north B > is along south B = 3160 (-j) ============= resultant (R) R = A+B R = 2080[cos 32.5 (i) + sin 32.5 (-j)] + 3160 (-j) R = 1754.254 (i) - 1117.583 (j) - 3160 (j) R = 1754.254 (i) - 4277.583 (j) |R| = [1754.254^2 + 4277.583^2]^1/2 = 4623.324 N direction tan (p) = - 4277.583 / 1754.254 = - 2.4384 p = 292.3 degree angle(p) made by Ris measured from (+x) or east counter-clockwise with is (-67.74 degree south of east clockwise)
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