Here is a picture http://www.google.com/imgres?um=1&hl=en&client=firefox-a&hs=0A
ID: 1900373 • Letter: H
Question
Here is a picture http://www.google.com/imgres?um=1&hl=en&client=firefox-a&hs=0AQ&sa=N&rls=org.mozilla:en-US:official&biw=1456&bih=700&tbm=isch&tbnid=FuKS2j_nHImmVM:&imgrefurl=http://iit.fundoobanda.com/2009/07/electrostatics-part-2gauss-law/&docid=xecyUQk2sw1MjM&imgurl=http://iit.fundoobanda.com/wp-content/uploads/2009/07/072409_0442_Electrostat29.png&w=386&h=352&ei=k0NbUISvIcjBygGpl4CACg&zoom=1&iact=hc&vpx=656&vpy=154&dur=2209&hovh=214&hovw=235&tx=94&ty=120&sig=101221964799010015029&page=1&tbnh=163&tbnw=177&start=0&ndsp=20&ved=1t:429,r:3,s:0,i:83A charge q at the origin is at the back corner of an imaginary cube of edge length a. What is the electric flux through the shaded region (the plane at y=a)? Work out the answer By direct integration (Hint: set up this problem with cartesian coordinates, not spherical coordinates)
Explanation / Answer
please check your question as there is too big URL for picture and there is no picture also again post so that i can help you what is this? http://www.google.com/imgres?um=1&hl=en&client=firefox-a&hs=0AQ&sa=N&rls=org.mozilla:en-US:official&biw=1456&bih=700&tbm=isch&tbnid=FuKS2j_nHImmVM:&imgrefurl=http://iit.fundoobanda.com/2009/07/electrostatics-part-2gauss-law/&docid=xecyUQk2sw1MjM&imgurl=http://iit.fundoobanda.com/wp-content/uploads/2009/07/072409_0442_Electrostat29.png&w=386&h=352&ei=k0NbUISvIcjBygGpl4CACg&zoom=1&iact=hc&vpx=656&vpy=154&dur=2209&hovh=214&hovw=235&tx=94&ty=120&sig=101221964799010015029&page=1&tbnh=163&tbnw=177&start=0&ndsp=20&ved=1t:429,r:3,s:0,i:83
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