A 3.00{\ m kg} piece of wood slides on the surface shown in the accompanying fig

Question

A 3.00{ m kg} piece of wood slides on the surface shown in the accompanying figure. All parts of the surface are frictionless, except for a 30.0{ m m} -long rough segment at the bottom, where the coefficient of kinetic friction with the wood is 0.200. The wood starts from rest 3.50{ m m} above the bottom.(Figure 1)

Figure 1: http://session.masteringphysics.com/problemAsset/1342984/2/1027497.jpg

Part A
Where will the wood eventually come to rest?
s = _____________{ m m}

Part B
How much work is done by friction by the time the wood stops?
W = ______________{ m J}

Explanation / Answer

mgh=0.5mv^2 v=5.86m/s frictional force= 0.2*3*9.8=5.88 deaccleration a=f/m=1.96 0=v^2-2as s=5.86^2/2*1.96 = 8.76m but the surface is just 3 m so the block wont stop but rather continue moving upward v after friction surfcae v^2=5.86^2-2*1.9*3 v=4.9m/s mgh=0.5mv^2 h=1.17m work done by friction=f*s=5.88*3=17.64

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