Given: A mass hangs on the end of a massless rope. The pendulum is held horizont

Question

Given: A mass hangs on the end of a massless rope. The pendulum is held horizontal and released from rest. When the mass reaches the bottom of its path it is moving at a speed v = 2.1 m/s and the tension in the rope is T = 17.9 N.

How long is the rope? I got .224 m

What is the mass? I got .606 kg

If the maximum mass that can be used before the rope breaks is mmax = 1.44 kg, what is the maximum tension the rope can withstand? (Assuming that the mass is still released from the horizontal.)

I got 42.47 kg

Now a peg is placed 4/5 of the way down the pendulum

Explanation / Answer

T = mv2/R = 0.606*1.875*1.875/(0.224/5) = 47.6 N

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