A 350kg piano slides 3.7m down a 33^\\circ incline and is kept from accelerating

Question

A 350kg piano slides 3.7m down a 33^circ incline and is kept from accelerating by a man who is pushing back on it parallel to the incline (see the figure(Figure 1) ). The effective coefficient of kinetic friction is 0.32.

Part A Calculate the force exerted by the man. Express your answer using two significant figures.

Part B Calculate the work done by the man on the piano. Express your answer using two significant figures.

Part C Calculate the work done by the friction force. Express your answer using two significant figures.

Part D Calculate the work done by the force of gravity. Express your answer using two significant figures.

Part E Calculate the net work done on the piano.

Explanation / Answer

a)Force exerted by man=mgSin-mgCos=947.6N

b)Work done by man=F.d=-3500J (- because force and displacement are opposite)

c)Work done by friction=mgCos*d=-3400J (- because force and displacement are opposite)

d)Work done by gravity=mgdSin=6900J

e)Net work done=Work done by man+Work done by friction+Work done by gravity=0

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