19. Consider the following pedigree below for a rare autosomal trait. Be sure to

Question

19. Consider the following pedigree below for a rare autosomal trait. Be sure to take into account the inbreeding convention, when needed. a. (1 pts)What is the probability that individual B is heterozygous? b. (1 pt) What is the inbreeding coefficient of individual E? c. (2 pts) After divorce, individual "A" decides to marry at random outside the pedigree. If the population allele frequency of the rare autosomal trait is 0.012, what are the chances of having an affected child for his first born of his second marriage? Ct B"

Explanation / Answer

One parent of C and her siblings is definitely carrier because sibling of A is infected. So the probability of C or her siblings being heterozygouus is 50% or 1/2. And B is the offspring of a parent having 1/2 probability for heterozygous condition then probability of B having heterozygous condition will be 1/2x1/2= 1/4.

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