A bullet of mass m1 is fired with a speed v into the bob of a ballistic pendulum

Question

A bullet of mass m1 is fired with a speed v into the bob of a ballistic pendulum of mass m2. Find the maximum height h attained by the bob if the bullet passes through the bob and emerges with a speed v/3. (Use any variable or symbol stated above along with the following as necessary: g.) h = ? I also know that Momentum is conserved in the collision of the bullet with the bob and kinetic energy is transformed into gravitational potential energy as the bob swings up to its maximum height. My first answer was m1v^2/9gm2. Please help!

Explanation / Answer

The mass of the bullet is m1 the mass of the block is m2 let the initial speed of the bullet is vi = v To complete the ciclre the combine block should contain speed at the bottom is v5gr so from law of conservaiton of momentum m1v1i = (m1+m2)vf m1v = (m+m2) v5gL since v5gl is the minimum speed at the bottom to the complete the circle. therefore the minimum speed of the bullet v = (m1 + m2)m1 (v5gL)

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