Suppose a 400 -kg alligator of length 3.7 m is stretched out on a board of the s
ID: 1906303 • Letter: S
Question
Suppose a 400-kg alligator of length 3.7 m is stretched out on a board of the same length weighing 95 N. If the board is supported on the ends as shown in the figure, and the scale reads 1,686 N, find the x-component of the alligator's center of gravity. (Let x = 0 correspond to the left end of the board.) m
Explanation / Answer
cg of the board = 3.5/2 0 = 3.5/2 * 65 + 416*g*x - 1800*3.5 solve for x x = (1800*3.5 - 3.5/2 * 65)/ (416*g)
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