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A particle is located at the vector position r = (5.00i + 8.00j) m and a force e

ID: 1907081 • Letter: A

Question

A particle is located at the vector position r = (5.00i + 8.00j) m and a force exerted on it is given by F = (3.00i + 2.00j) N. What is the torque acting on the particle about the origin? tau = N . m Can there be another point about which the torque caused by this force on this particle will be in the opposite direction and half as large in magnitude? Can there be more than one such point? Can such a point lie on the y axis? Can more than one such point lie on the y axis? Determine the position vector of one such point. (Give a point on the y axis.) r = m

Explanation / Answer

torque acting = FXR = 24-10 =14 N-m the point =(0,7) =0i+7j cheers :)

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