Flow Problem, Pipe (7) A pipe with a diameter of D1 =9cm rises vertically a heig

Question

Flow Problem, Pipe (7) A pipe with a diameter of D1 =9cm rises vertically a height H =3.4m and expands to a pipe of D2 =34cm in diameter. The flow rate of the fluid through the pipe is6?10?2cubic meters per second. The pressure in the lower end of the pipe is1.5?105Pascals. The fluid has a density of0.7kg/m3..

Part A Find the velocity of the water in the lower section of the pipe.

V1= m/s

Part B Find the difference in hydrostatic pressure from the high section to the low section.

PH= Pascals

Part C Find the pressure in the upper section of the pipe.

P2= Pascals

Part D

What is the weight of the fuid that passes through the pipe in11?

Weight of Fluid = Newtons

Explanation / Answer

As we know

Q = AV = Consatnt

Therefore

V1 = (6*10^-2)/(0.25*pi*(9*10^-2)^2)

= 9.43 m/sec

Ath the Lower part

P + gh + 0.5V1^2 = Constant

Therefore

Consant = 1.5*10^5 + 0.7*9.8*0 + 0.5*0.7*9.43^2

= 150031.1237

So

At the Top POint

P + gh + 0.5V2^2 = Constant

At the Top Point

V2 = (6*10^-2)/(0.25*pi*0.34^2)

= 0.66 m/sec

Therefore

P = 150031.1237 - (0.7*9.8*3.4 + 0.5*0.7*0.66^2)

= 150007.647 Pa

P = 150007.647 - 150000

= 7.647 Pa

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