A particle moves along the x axis. It is initially at the position 0.110 m, movi

Question

A particle moves along the x axis. It is initially at the position 0.110 m, moving with velocity 0.210 m/s and acceleration -0.430 m / s2. Suppose it moves with constant acceleration for 3.20 s. Find the position of the particle after this time. m Find its velocity at the end of this time interval. m/s Next, assume it moves with simple harmonic motion for 3.20 s and x = 0 is its equilibrium position. (Assume that the velocity and acceleration is the same as in parts (a) and (b).) Find its position. m Find its velocity at the end of this time interval. m/s

Explanation / Answer

a)-1.4196 m b)-1.166 m/s c)x= A coswt Aw= 0.21 Aw^2 = 0.43 w = 2.0476 A =0.102 x= 0.098 m d)-0.0555 m/s

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