On a car customization show it was mentioned that when placing bigger wheels (an

Question

On a car customization show it was mentioned that when placing bigger wheels (and thinner tires) on a car, you must put bigger brakes on the car in order to stop it. Consider two wheels, both have a mass of 23 kg and both are accelerated at -0.63 rad/s2. The standard wheel can be modeled as a hoop (ring) with all the mass located at radius 22 cm. The tricked-out wheel is also a hoop with all the mass located at 25 cm. How much more torque must be applied to stop the tricked-out wheel compared to the standard wheel?

Explanation / Answer

I = mr^2 I1 = 1.1132 I2 = 1.4375 T = I* alpha Here |a| = 0.63 rad/s^2 So, T2 - T1 = a(I2 - I1) = 0.204 N - m

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