a) What is the maximum value for the oscillating current assuming no resistance

Question

a) What is the maximum value for the oscillating current assuming no resistance in the circuit. Answer in units of A.

b) What is the maximum energy stored in the magnetic field of the inductor? Answer in units of J.

A LC circuit is shown in th efigure below. The 48 pF capacitor is initially charged by the 9 V battery when S is at position a. Then S is thrown to position b so that the capacitor is shorted across the 12 mH inductor. a) What is the maximum value for the oscillating current assuming no resistance in the circuit. Answer in units of A. b) What is the maximum energy stored in the magnetic field of the inductor? Answer in units of J.

Explanation / Answer

Initial charge on capacitor = volts x capacitance = 9 x 48 x 10^-12 C = 432 x 10^-12 C

Energy stored in Capacitor = 1/2 x C x V^2 = 1/2 x 48 x 10^-12 x 9^2 = 1944 x 10^-12 J = E

Also, E = 1/2 x L x Imax^2, Solve to find Imax

Maximum energy stored in the inductor = E (when all the capacitive energy converts to inductive energy)

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