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the organ pipe is 2.75 m long. what is the frequency of the standing wave shown

ID: 1913546 • Letter: T

Question

the organ pipe is 2.75 m long. what is the frequency of the standing wave shown in the pipe? what is the fundamental frequency of the pipe?

Explanation / Answer

fixed end >> always N (Node) open end >> always A (Antinode) -------------------------------- distance N to N = ?/2 = distance A to A L = length of pipe = N to N + N to A = ?/2 + ?/4 L = 3?/4 = 2.75 so > ? = 4*2.75/3 = 3.6667 m speed of sound in air (v) = 343 m/s freq (f) = v / ? = 343/3.667 = 93.5454 Hz ==================== b) for fundamental freq (fo) pipe need to accomodate (quarter wave only or N to A) L = N to A = ?/4 = 2.75 ? = 2.75*4 = 11 m fo = v/? = 343/11 = 31.1818 Hz

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