A 2.00 kg frictionless block is attached to a horizontal spring as shown. At t =

Question

A 2.00 kg frictionless block is attached to a horizontal spring as shown. At t = 0, the position x = 0.225 m, and the velocity is 4.25 m/s toward the right in the positive x direction. Position x as a function of t is: x = A*cos(?t ) , where A is the amplitude of motion and ? is the angular frequency discussed Chapter 11 and the notes. (a) What is the spring constant k? (b) Use conservation of energy to compute amplitude A. (c) How much farther from the point shown will the block move before it momentarily comes to rest before turning around? (d) What is the period T of the motion? (e) If the mass of this problem was doubled to 4.00 kg, how would your answer to part (d ) change?

Explanation / Answer

IF the position were correctly given as x = A cos(omega t), and IF the position at t=0 is 0.225 m, then the amplitude would be 0.225 m; but this actually doesn't make any sense, because the block is still moving to the right when x = 0.225 m. So we have to guess which of the assertions in the problem statement is false. But I'm not going to. You should just point out to your teacher that the assertions in the problem statement are self-contradictory.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.