The Shanghai Maglev train can travel at speeds up to 431[km=hr]. The Pudong Inte

Question

The Shanghai Maglev train can travel at speeds up to 431[km=hr]. The Pudong International Airport is approximately 18:6[miles] away from a very popular train stop. Assuming the train has an average speed during a trip from the train stop to the airport of 250[km=hr], how long will it take to make the trip [minutes]. Assuming the train can accelerate to its fastest speed in 5[s], determine the average acceleration in [m=s2] and g's Research how many g's the human body can experience prior to passing out, and determine the speed the train would have to achieve in 5[s] to create this threshold level of g's. Assuming it's 17 G's for the max threshold. Show work please!!

Explanation / Answer

WE KNOW: d = 18.6 miles = 29.76 km speed = v = 250 kmph time = d/v = 29.76/250 ) x 60 mi utes = 7.1424 minutes

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