50J of work are done per cycle on a refrigerator with a coefficient of performan

Question

50J of work are done per cycle on a refrigerator with a coefficient of performance of 3.0. A) How much heat is extracted from the cold reservoir per cycle? (in J) Express your answer using two significant figures. B) How much heat is exhausted to the hot reservoir per cycle? (in J) Express your answer using two significant figures.

Explanation / Answer

The fridge is heat a pump used for cooling. For such operation coefficient of performance is defined as ratio of heat extracted from cold reservoir to the work done on the pump: COP = Qc/W => Qc = W · COP = 50J · 3 = 150J Conservation of energy requires that the total energy absorbed by work and heat from cold reservoir is exhausted to the hot reservoir, i.e. Qh = W + Qc = 50J + 150J = 200J

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