Design a combination of identical capacitors, each with capacitance C, for which

Question

Design a combination of identical capacitors, each with capacitance C, for which the equivalent capacitance is 3C/4. (Select all that apply. ) Make C/4 capacitors by combining four capacitors in series; then combine three of these in parallel. Connect three capacitors in parallel to obtain an equivalent capacitance of 3C; then connect four of these new capacitors in series. Make C/4 capacitors by combining four capacitors in parallel; then combine three of these in series. Connect three capacitors in series to obtain an equivalent capacitance of 3C; then connect four of these new capacitors in parallel. Make 4C capacitors by combining four capacitors in series; then combine three of these in parallel. Connect four capacitors in parallel to obtain an equivalent capacitance of 4C; then connect four of these new capacitors in series.

Explanation / Answer

Parallel capacitors add up. Ceff=C1+C2+... Series capacitors follow this: 1/Ceff=1/C1+1/C2... If there are n capacitors in series then 1/Ceff=1/C+1/C+..n times=n/C So we get Ceff=C/n. Using the above we get: (a),(b)

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