Design a combinational circuit that accepts a 3-bit number and generates a 6-bit
ID: 441556 • Letter: D
Question
Design a combinational circuit that accepts a 3-bit number and generates a 6-bit binary number equal to the square of the number. Thanks!Explanation / Answer
Start with a truth table: ABC => UVWXYZ 000 => 000000 001 => 000001 010 => 000100 011 => 001001 100 => 010000 101 => 011001 110 => 100100 111 => 110001 If you look down the columns, you can model the circuit as 6 distinct circuits -- one for each output bit. You might want to create a small K-map for each function if the logic isn't obvious from direct inspection. A couple of them are quite simple. For example, note that the output for Y is *always* zero (just look down the column of values under the "Y"). You might note that the output for Z always equals the input from C. The six output functions are: U = AB V = AB' + AC W = A'BC + AB'C X = BC' Y = 0 Z = C I presume it's obvious that the combined circuit can be implemented directly from these logic equations.
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