The 75,000-kg Space Shuttle needs to boost itself from its current orbit (altitu
ID: 1919061 • Letter: T
Question
The 75,000-kg Space Shuttle needs to boost itself from its current orbit (altitude 250 km)to the orbit of the Hubble Space Telescope (altitude 610 km). How much energy does this boost require? A 20 kg satellite has a circular orbit (period = 2:24:00; circumference = 5.00 times 107 m)around a planet of unknown mass and size. Find the speed of the satellite in its circular orbit Find the radial acceleration of the satellite Find the mass of the planet. Local g on the surface of the planet is found to be 8.00 m/s2. Find the radius of the planet. At what minimal radial speed (directly away from the planet)would the satellite need to be moving in order to escape from the planet's gravitational field?Explanation / Answer
a)Total energy of that satellite is (-G.M.m) / (2.R) where:
G = Gravitational constant = 6.673 x 10^(-11) (N . m^2) / (kg^2)
M = Mass of the earth = 6 x 10^(24) kg
m = Satellite's mass = 75000 kg
R = radius of satellite's orbit
Energy to be provided will be
((-G.M.m) / (2))*((1/R2)-(1/R1))
where R2 = radius of outer orbit (radius of earth + altitude : 6353+610 = 6963 km)
R1 = radius of inner orbit (6353 + 250 = 6603 km)
The answer comes out to be 1.17 x 10^11 Joules.
need some time for b part....
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