A. Chi-Square Problems involving Geneties 1. The following are dihybrid Fa data
ID: 193062 • Letter: A
Question
A. Chi-Square Problems involving Geneties 1. The following are dihybrid Fa data (AaBb x AaBb) 2, and answer on your calculations,nt? Complete ). Do the data support the hypothesis of Phenotype O-E (O-E) (O-E)/E A-B- 406 A-bb 149 aaB. aabb Totals 162 51 gres of fedom. a. In interpreting this X2 value, you havede b. In this case do you accept or reject the hypothesis that these data approximate the dihybrid F2 ratio expected with independent assortment? Explain your response c. What is the probability that the deviations from the expected are due to chance alone Explain your responseExplanation / Answer
Here observed value is given but expected value will be according to the ratio 9:3:3:1. Thus, the expected value will be as obtained by multiplying the minimum value (51) with 9, 3,3 and 1.
Here value of X2 = 6.752
a. Degree of freedom = N -1. Here N number of sample (type of classes of progeny). Here four classes of progeny are present. Therefore the value of N = 4 and degree of freedom will be 4-1 = 3
b. Here the hypothesis is accepted because the value of X2 is within the critical value of X2 (Here the critical value of X2 is 7.815 at the alpha level 0.05 and degree of freedom 3. The critical value is taken from chi square distribution table).
c. Here deviation from expected result is only due to chance alone because the value of X2 is within the limit of critical value. Thus, the probability is 100%.
Phenotype O E O-E (O-E)2 (O-E)2/E AABB 406 459 -53 2809 6.119 AAbb 149 153 -4 16 0.104 aaBB 162 153 9 81 0.529 aabb 51 51 0 0 0 Total 6.752Related Questions
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