Find the value of Vs in the network in the Figure such that the power supplied b

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Two resisters are in series =>R1 = 150 + 150 = 300 O Now 300O and 150 O are in parallel =>1/R(net) = 1/300 + 1/150 =>R(net) = 100O =>By V = iR =>i = V/R = 3.6/100 = 0.036 Amp =>(b) If you look carefully at the triangle of resistors, you can see that you have the resistor across which the supply is connected, and the other two are in series with each other but are in parallel with the resistor that has the supply across it. So the total resistance is (150 + 150) in parallel with 150, which is 300 across 150, so Resistance = Product / Sum = (300 * 150) / (300 + 150) = 300 * 150 / 450 = 100 ohms From Ohm's law current = V / R = 3.6 / 100 = 0.036 A

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