What happens when you have a non-zener and zener diode in series opposing each o

Question

What happens when you have a non-zener and zener diode in series opposing each other eg non-zener is forward bias and the zener is reverse bias assuming both are ideal (infinite slopes when they are operating).

Vf for both of them is 0.5 and the breakdown voltage for the zener is 2.

what would the graph of current vs voltage graph for them in series be?

would the graph have a line upwards at -1.5 or no upward lines at all

I am confused at where the graph is defined and if any current flows through the diodes because i am unsure if the greater breakdown voltage than the forward bias voltage effects the currents direction which would cause the non-zener diode to become reverse bias.

sorry for the amount of text but i am unsure who to explain my problem i am having, thanks in advance for any help i receive and i will rate answers.

Explanation / Answer

Zener diode is not a linear device... it is non-linear one. Since linear devices are those devices which have linear characteristics(V-I CHAR.), or follows the Ohm's law i.e. voltage is directly proportional to current. It allows current to flow in the forward direction in the same manner as an ideal diode, but will also permit it to flow in the reverse direction when the voltage is above a certain value known as the breakdown voltage. But as there is a Non Zener diode in the reverse mode it will provide obstruction in the current flow.But if there's a Voltage breakdown a reverse flow of current the non Zener diode will be Forward bias position n will allow the current to flow.

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