A certain 2 terminal network has an input impedance of 5-j8 Ohm. At a frequency

Question

A certain 2 terminal network has an input impedance of 5-j8 Ohm. At a frequency of 4000 rad/sec inductance should be placed in parallel with the network to cause the input impedance to have zero reactance have a magnitude of 4 Ohm. z = -j/4000 times 10 times 10-6 = -j/0.04 = -12.5 Ohm z = -j (12.5)(4)/(4)-j12.5 + jwL(4000L) z = -j312.5/4 - j12.5 + jwL (4) - j12.5/4 - j12.5 z = -j312.5 + 4 jwL + 12.5wL/4 - j12.5 z = -j (312.5 - 4)(4 + 12.5) + 12.5 wL (4 + j12.5)/781.25 z = (4)(-j125) + (j4000L)(4-j12.5)/(4 - j12.5)

Explanation / Answer

you make a calculation mistake please check your calculation method is coreect

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