Part E Imagine that you attempted to recreate Mendel\'s work with garden peas. Y

Question

Part E Imagine that you attempted to recreate Mendel's work with garden peas. You began by crossing true breeding violet-flowered, tall plants with white-flowered dwarf plants Use a chi-square analysis to test the hypothesis that the F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation After self-crossing the F1 generation, you obtain the following phenotypes in the F2 generation 80 tall, violet flowers 36 tall, white flowers 39 dwarf, violet flowers 5 dwarf, white flowers Calculate the chi square value Express your answer to two decimal points (example: 100.00) Probability IP) Value 0.50 0016 0.21 0.58 1.06 1.61 0.50 0.46 1.39 2.37 3.36 4.35 5.35 6.35 7.34 030 1.07 2.41 3.67 005 384 5.99 0.10 2.17 4.61 0.95 0.70 020 0.01 0.001 0.15 164 0.10 0.35 0.71 1.15 1.64 2.17 2.73 9.21 78211.35 13.28 15.09 16.81 18.48 13.82 16.27 1847 20.52 22.46 2432 26.13 7.51 1.42 2.20 3.00 3.83 467 5.53 7.78 9.24 10.65 949 1107 2.59 4.07 1551 729 7.23 Submit Request Answer 2.83 349 9.52 11.03 13.36 Incorrect; One attempt remaining: Try Again Keep in mind this question is asking only about stem height, not flower color. Determine the total number of plants with tall or dwarft stem height and then try the chi square test again

Explanation / Answer

Answer:

Based on the given information:

True breeding violet-flowered tall plants x White flowered dwarf plants

Let tall plants allele be represented by: T and dwarf plants allele be represented as t

The genetic cross will lead to a 9:3:3:1 ratio

Expected frequency based on Mendels law of segregation:

Chi Square analysis (for only stem height - tall or dwarf) can be performed as below:

Therefore, Chi square value for stem length (tall:dwarf) is 0.533

Phenotype Observed Frequency (O) Expected Frequency (E) (O-E) (O-E)^2/E Tall plants   (80+36) = 116 (90+3) = 120 -4 0.133 Dwarf plants (39+5) = 44 (30+10) = 40 4 0.400 Chi Square (sum) 0.533

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