Question 1 and 2!! 1. Determine the gene order and phase for the genes A, B and

Question

Question 1 and 2!! 1. Determine the gene order and phase for the genes A, B and C. 2. Determine the distance between genes A, B and C. 3. Draw a linkage map with the correct gene order, allele combinations on each chromatid and distance between the three genes. For this exercise, phenotypes with capital letters are dominant and phenotypes in lower case letters are recessive. For example, "phenotype A" mean the dominant phenotype for the gene and "phenotype a" means the recessive phenotype for that gene. Show all your calculations. Remember that the three genes can be in any order. Remember that the dominant alleles do not necessarily need to all be on the same chromosome in the triple heterozygote parent. Phenotypes N 309 305 aTB Atb ATb atB atb ATB AtB aTb Total 51 54 3 4 56 61 843

Explanation / Answer

1) the higehst number is the NCO(non cross overs)=309,305 least is the DCO(double cross over)=3,4

aTB Atb= NCO atb ATB=DCO

now consider one NCO and one DCO aTB atb here T changes to t and B (of NCO)changes to b(of DCO) the 'a' remains the same . 'a' behave oddly. The one gene which behave oddly will be in the centre. ie a

gene orde =TaB =309 tAb=305 DCO atb=3 ATB=4

SCO1:taB=54 TAb==51

SCO2: Tab=61 tAB=56

Distabce between T and a= [SCO1 +DCO/total] * 100=54+51+3+4/843 *100=13.28cM

Distance between B and a = [SCO2 +DCO/total] * 100=61+56+3+4/843 *100=14.7cM

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