A sled of mass m is given a kick on a frozen pond. The kick imparts to the sled

Question

A sled of mass m is given a kick on a frozen pond. The kick imparts to the sled an initial speed of 2.00 m/s. The coefficient of kinetic friction between sled and ice is 0.100. Use energy considerations to find the distance the sled moves before it stops.

Here is what I have so far but I am a little lost....Please provide further detail

Find the deceleration:

Fnet = Ffric
ma = umg
a = ug
a=(0.1)(9.8 m / s^2)
a=0.98 m / s^2

Since this is a deceleration rate, then it should be negative. Then,

a=-0.98 m / s^2

formula for displacement

d=[vf^2-vi^2 ]/[2a]

Since the sled will be stopping, then vf = 0 m/s. We now have

d=[(0 m / s-(m m / s ^2 ]/[2-0.98 m /s^2]

Explanation / Answer

I would have done this problem like this:

Energy = Force x Distance; Energy is in form of Kinetic energy

KE = F*d

(.5)mv² = F*d

(.5)mv² = mgµ * d

(.5)v² = gµd

d = (.5) (v² / gµ)

d = (.5)(2.00m/s)² / [(9.81m/s²)(0.100)]

d = 2.04 m

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