Five recessive maize mutants were isolated ( d1-d5 ), which are defective in pig

Question

Five recessive maize mutants were isolated (d1-d5), which are defective in pigment biosynthesis. Wild type corn kernels are Red (R), the d1-d5 mutant kernels are Yellow (Y). To test if any of these (d1 to d5) mutations are allelic to each other, you did complementation tests (pairwise crosses) and the resulting F1 phenotype is shown in the Table 1 below. How many genes are represented by these five mutations? How are these five mutations grouped into different complementation groups? (R(red) and Y(yellow)).

d1

d2

d3

d4

d5

d1

Y

R

R

R

R

d2

Y

R

Y

R

d3

Y

R

Y

d4

Y

R

d5

Y

d1

d2

d3

d4

d5

d1

Y

R

R

R

R

d2

Y

R

Y

R

d3

Y

R

Y

d4

Y

R

d5

Y

Explanation / Answer

From the results, we can interpret that

Overall, 3 complementation groups are formed.

Complementation group 1: d2 and d4

Complementation group 2: d3 and d5

Complementation group 1: d1

Presence of 3 complementation groups indicate that the trait is controlled by atleast 3 genes. It can be more than 3 genes, however we did not get any mutations on the other genes by chance.

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