Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Five objects of equal mass are shown below together with the axis about which th

ID: 1976269 • Letter: F

Question

Five objects of equal mass are shown below together with the axis about which they are rotating. Select from the pull-down menus the objects in order of increasing rotational energy, with 1 having the smallest rotational energy and 5 having the highest rotational energy.

a) Solid Cylinder, about cylinder axis with R = 3 m and gw = 4 rad/s

b) Thin Spherical shell, about any diameter, with R = 3 m and gw = 4 rad/s

c) Thin rod, about axis through center, perpendicular to the length with l = 9 m and gw = 4 rad/s

d) Thin cylindrical shell, about cylinder axis with R = 2 m and gw = 5 rad/s

e) Solid Sphere, about any diameter, with R = 4 m and gw = 4 rad/s

Five objects of equal mass are shown below together with the axis about which they are rotating. Select from the pull-down menus the objects in order of increasing rotational energy, with 1 having the smallest rotational energy and 5 having the highest rotational energy. a) Solid Cylinder, about cylinder axis with R = 3 m and ?gw = 4 rad/s b) Thin Spherical shell, about any diameter, with R = 3 m and ?gw = 4 rad/s c) Thin rod, about axis through center, perpendicular to the length with l = 9 m and ?gw = 4 rad/s d) Thin cylindrical shell, about cylinder axis with R = 2 m and ?gw = 5 rad/s e) Solid Sphere, about any diameter, with R = 4 m and ?gw = 4 rad/s

Explanation / Answer

a) For solid cylinder        RK   = 0.5 I 2                 = 0.5 (0.5 M R2) 2                 = 0.25 M R2 2                 = 0.25 x M x 9 x 16                 = 36 M b) For solid cylinder        RK   = 0.5 I 2                 = 0.5 (0.666 M R2) 2                 = 0.333 M R2 2                 = 0.333 x M x 9 x 16                 = 48 M c) For thin rod I = ML2 / 12 = M x 81 / 12 = 6.75 M RK   = 0.5 I 2                 = 0.5 (ML2 / 12) 2                 = 0.5 (6.75M 2 )                 = 0.5x 6.75M x 16                 = 54 M d) I = 025 M R2       RK   = 0.5 I 2                 = 0.5 (0.25M R2) 2                 = 0.125 M R2 2                 = 0.125 x M x 4x 25                 = 12.5 M e) I = 2MR2 / 5    RK   = 0.5 I 2                 = 0.5 (0.4 M R2) 2                 = 0.2 M R2 2                 = 0.2x M x 16 x 16                 = 51.2 M Therefore             c >   e > b > a > d