a speeding motorcyclist is traviling at a constant speed of 36m/s when he passes
ID: 1955183 • Letter: A
Question
a speeding motorcyclist is traviling at a constant speed of 36m/s when he passes a police car parked on the side of the road. The radar , positioned in the police car's rear window, measures the speed of the motorcycle .At the instant the motorcycle passes the police the police start to chase him with constant acceleration of 4.0m/s^2.A)how long it take the police officer to catch the motorcyclist?
B)what is the speed of the police car when it catches up to the motorcycle?
c)how far the police car be from its original position?
Explanation / Answer
a) Given a constant speed, v = 36 m/s, the distance the motocyclist travels, m, is given by: m = vt = 36t Given a constant acceleration, a = 4.0 m/s², the distance the police travels, p, is given by: p = (1/2)at² = (1/2)(4)t² = 2t² When the distances are the same, the police will have caught up with the motocyclist: m = p 36t = 2t² 36 = 2t t = 36/2 = 18 s b) The speed of the police car is: v = at = (4.0)(18) = 72 m/s c) The police car traveled: p = 2t² = 2(18)² = 648 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.