(a) What is the magnitude, F , of the applied force? (b) What is the contact for
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Question
(a) What is the magnitude, F, of the applied force?
(b) What is the contact force between the blocks?
(c) What is the net force acting on block 1?
Two blocks are in contact on a frictionless, horizontal tabletop. An external force, F, is applied to block 1, and the two blocks are moving with a constant acceleration of 2.05 m/s2. Use M1 = 3.04 kg and M2 = 6.00 kg. (a) What is the magnitude, F, of the applied force? (b) What is the contact force between the blocks? (c) What is the net force acting on block 1? magnitude
Explanation / Answer
a) Total mass = 3.04 + 6 = 9.04 kg F = ma = 9.04 * 2.05 = 18.532 N b) Contact force = ma = 6 * 2.05 = 12.3 N c) net force = ma = 3.04 * 2.05 = 6.232 N
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