I\'ve worked this problem 3 different times, with 3 different answers... A car i
ID: 1959595 • Letter: I
Question
I've worked this problem 3 different times, with 3 different answers...
A car is travelling at 45 mph; the driver sees a stop sign 150 ft ahead and hits the brakes, and decelerates at 11.4 ft/s2. How fast is the car going as it passes the stop sign?
I've calculated that it takes 5.8 s to come to a complete stop, and the distance travelled is 191 ft. But the velocity as it passes the stop sign I'm getting 1.93 s, about 4 s, and over 8 s...I'm fairly certain the last one has to be wrong. Unless I miscalculated the time & distance it takes to stop of course. Help!
Explanation / Answer
intail velocity u = 45 mph =20 m/s (1 mph = 1601m/3600s)
s = 150 ft = 46.15 m ( 1m = 3.25 m)
a = -11.4 ft /s^2 = - 3.50 m/s^2
v =?
we know
v2 - u2 =2as ,
v2 = 76.40
solving we get v= 8.73 m/s
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