I got the first part, but forgot the second [art of this question. Thank you for

Question

I got the first part, but forgot the second [art of this question. Thank you for your help!!

You push a 66 { m kg} box across a floor where the coefficient of kinetic friction is mu _{ m{k}} = 0.55. The force you exert is horizontal.

How much power is needed to push the box at a speed of 0.60 { m m/s}? P = 355.74W
Power = Force * Velocity; Force = .55 *66kg*9.81m/s^2 = 355.74
Power = 355.74 * .60 m/s = 213.44 W.

Now I am having trouble figuring out the second part:
How much work do you do if you push the box for 34 { m s}?

Explanation / Answer

Power=work/time hence work= power*t= 213.44*34= 7256.96 J

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