Given: A 2-D force and couple system as shown. Find: The equivalent resultant fo

Question

Given: A 2-D force and couple system as shown. Find: The equivalent resultant force and couple moment acting at A and then the equivalent single force location along the beam AB. Plan: Sum all the x and y components of the forces to find FRA. Find and sum all the moments resulting from moving each force to A. Shift the FRA to a distance d such that d = MRA/FRY + rightarrow FRx = 25 + 35 sin 30 degree = 42.5 lb + downarrow FRy = 20 + 35 cos 30dgree = 50.31 lb +(MRA= 35cos30 degree(2) + 20(6)-25(3) = 105.6 Ib.ft FR = (42.52 + 50.312 )1/2 = 65.9 lb theta = tan-1 (50.31/42.5) =49.8 degree The equivalent single force FR can be located on the beam AB at a distance d measured from A. d = MRA/FRY = 105.6/50.31 = 2.10 ft. 2-1 need another method to get d

Explanation / Answer

I believe the reason why there is the -25(3) term would be because of the restoring force from the wall. That is the only thing I can see from the diagram causing one of the terms to be negative. Breaking these problems down into force x-vectors, y-vectors, blah blah always clears things up a bit. Pulley problems are about thinking + math, force diagrams are about doing the math.

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